Set all line styles in an Enterprise Architect diagram automatically

With this script you can change set all the lines styles on a diagram at once, to your preferred style per type of connector.

In Enterprise Architect you can choose from no less then 9 different line styles for the connectors.

Line Styles

Unfortunately you can only choose from the first three to be the default line style for new connectors. Additionally you can also specify the default for Generalization to be Tree Style, but that is it.

For me that is not enough. I have my own habits when making UML diagrams. For most connector types I use Orthogonal – Square, but not for dependencies, use case relations and note links. For those I like the Direct style. The last exception are the control flow, state flow and object flows, for which I use Orthogonal – Rounded.

LineStylesDiagram

With this script I can set all the line styles on a diagram to the styles that I like.  All I need to do is right click on a diagram and choose Scripts|Set Line Styles

Set Linestyles menu option

And the script will set all the line styles to the defaults set in the script. If you would like the line styles to be set to your preferences automatically without having to run the script you can use EA-Matic version of this script.

You can set your own preferences in this section of the script

'*********EDIT BETWEEN HERE*************
' set here the menu name
menuDefaultLines = "&Set default linestyles"
' set here the default style to be used
defaultStyle = lsOrthogonalSquareTree
' set there the style to be used for each type of connector
function determineStyle(connector)
    dim connectorType
    connectorType = connector.Type
    select case connectorType
        case "ControlFlow", "StateFlow","ObjectFlow","InformationFlow"
            determineStyle = lsOrthogonalRoundedTree
        case "Generalization", "Realization", "Realisation"
            determineStyle = lsTreeVerticalTree
        case "UseCase", "Dependency","NoteLink"
            determineStyle = lsDirectMode
        case else
            determineStyle = defaultStyle
    end select
end function
'************AND HERE****************

Free download

Video

This script has been previously featured in the webinar Introduction to Scripting with Enterprise Architect presented by yours truly.

The script

option explicit
!INC Local Scripts.EAConstants-VBScript
' Script Name: DefaultLineStyles
' Author: Geert Bellekens
' Purpose: Allows to change the linestyles to their default
' Date: 27/04/2015
'
dim lsDirectMode, lsAutoRouteMode, lsCustomMode, lsTreeVerticalTree, lsTreeHorizontalTree, _
lsLateralHorizontalTree, lsLateralVerticalTree, lsOrthogonalSquareTree, lsOrthogonalRoundedTree
lsDirectMode = "1"
lsAutoRouteMode = "2" 
lsCustomMode = "3"
lsTreeVerticalTree = "V"
lsTreeHorizontalTree = "H"
lsLateralHorizontalTree = "LH"
lsLateralVerticalTree = "LC"
lsOrthogonalSquareTree = "OS"
lsOrthogonalRoundedTree = "OR"
dim defaultStyle
dim menuDefaultLines

'*********EDIT BETWEEN HERE*************

' set here the default style to be used
defaultStyle = lsOrthogonalSquareTree
' set there the style to be used for each type of connector
function determineStyle(connector)
	dim connectorType
	connectorType = connector.Type
	select case connectorType
		case "StateFlow","ObjectFlow","InformationFlow"
			determineStyle = lsOrthogonalRoundedTree
		case "Generalization", "Realization", "Realisation"
			determineStyle = lsTreeVerticalTree
		case "UseCase", "Dependency","NoteLink"
			determineStyle = lsDirectMode
		case else
			determineStyle = defaultStyle
	end select
end function
'************AND HERE****************

sub main
		dim diagram 
		dim diagramLink
		dim connector
		dim dirty
		dirty = false
		set diagram = Repository.GetCurrentDiagram
		'save the diagram first
		Repository.SaveDiagram diagram.DiagramID
		'then loop all diagramLinks
		if not diagram is nothing then
			for each diagramLink in diagram.DiagramLinks
				set connector = Repository.GetConnectorByID(diagramLink.ConnectorID)
				if not connector is nothing then
					'set the connectorstyle
					setConnectorStyle diagramLink, determineStyle(connector)
					'save the diagramlink
					diagramLink.Update
					dirty = true
				end if
			next
			'reload the diagram if we changed something
			if dirty then
				'reload the diagram to show the link style
				Repository.ReloadDiagram diagram.DiagramID
			end if
		end if
end sub
main

'gets the diagram link object
function getdiagramLinkForConnector(connector, diagram)
	dim diagramLink 
	set getdiagramLinkForConnector = nothing
	for each diagramLink in diagram.DiagramLinks
		if diagramLink.ConnectorID = connector.ConnectorID then
			set getdiagramLinkForConnector = diagramLink
			exit for
		end if
	next
end function
'actually sets the connector style
function setConnectorStyle(diagramLink, connectorStyle)
	'split the style into its parts
	dim styleparts
	dim styleString
	styleString = diagramLink.Style
	styleparts = Split(styleString,";")
	dim stylePart
	dim mode
	dim modeIndex
	modeIndex = -1
	dim tree
	dim treeIndex
	treeIndex = -1
	mode = ""
	tree = ""
	dim i
	'find if Mode and Tree are already defined
	for i = 0 to Ubound(styleparts) -1 
		stylePart = styleparts(i)
		if Instr(stylepart,"Mode=") > 0 then
			modeIndex = i
		elseif Instr(stylepart,"TREE=") > 0 then
			treeIndex = i
		end if
	next
	'these connectorstyles use mode=3 and the tree
	if  connectorStyle = lsTreeVerticalTree or _
		connectorStyle = lsTreeHorizontalTree or _
		connectorStyle = lsLateralHorizontalTree or _
		connectorStyle = lsLateralVerticalTree or _
		connectorStyle = lsOrthogonalSquareTree or _
		connectorStyle = lsOrthogonalRoundedTree then
		mode = "3"
		tree = connectorStyle
	else
		mode = connectorStyle
	end if
	'set the mode value
	if modeIndex >= 0 then
		styleparts(modeIndex) = "Mode=" & mode
		diagramLink.Style = join(styleparts,";")
	else
		diagramLink.Style = "Mode=" & mode& ";"& diagramLink.Style
	end if
	'set the tree value
	if treeIndex >= 0 then
		if len(tree) > 0 then
			styleparts(treeIndex) = "TREE=" & tree
			diagramLink.Style = join(styleparts,";")
		else
			'remove tree part
			diagramLink.Style = replace(diagramLink.Style,styleparts(treeIndex)&";" , "")
		end if
	else
		diagramLink.Style = diagramLink.Style & "TREE=" & tree & ";"
	end if
end function
function getConnectorStyle(diagramLink)
	'split the style
	dim styleparts
	styleparts = Split(diagramLink.Style,";")
	dim stylePart
	dim mode
	dim tree
	mode = ""
	tree = ""
	for each stylepart in styleparts
		if Instr(stylepart,"Mode=") > 0 then
			mode = right(stylepart, 1)
		elseif Instr(stylepart,"TREE=") > 0 then
			tree = replace(stylepart, "TREE=", "")
		end if
	next
	if tree <> "" then
		getConnectorStyle = tree
	else
		getConnectorStyle = mode
	end if
end function
2 replies
  1. Maksim Kurnitsky
    Maksim Kurnitsky says:

    Hi, Geert!
    thank you for this script!

    lsLateralVerticalTree = “LC” – should be “LV” here?

    Reply

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